20 Jan 2025, 12:06

@sktsec said in Find the highest (or lowest) close of x bars:

@MT4Nutzer
Initiate then use the loop block and a condition block.

Support x is the result

Initiate x (such as close the start candle)
Loop x time for the candles
Use condition block to compare x and close
save any new value to x

Thank you @sktsec . I want to try it.